document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287538>Question 287538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Upon graduation Sheldon decides to go to work for a local police department. His starting salary is $30000 per year and he expects to get a 3% raise per year. Write the recursion formula for a sequence that represents his salary n years on the job. Assume n=0 represents his first year making $30000. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208341 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Upon graduation Sheldon decides to go to work for a local police department. His starting salary is $30000 per year and he expects to get a 3% raise per year. Write the recursion formula for a sequence that represents his salary n years on the job. Assume n=0 represents his first year making $30000.<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "1st Yr: 1------30000<BR>\n" );
document.write( "2nd Yr: 2------30000+30000(0.03) = 30000(1.03)<BR>\n" );
document.write( "3rd Yr: 3------30000(1.03)^2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "...<BR>\n" );
document.write( "nth Yr: n-1------30000(1.03)^(n-1)<BR>\n" );
document.write( "========================================<BR>\n" );
document.write( "a(n) = 30000(1.03)^(n-1)<BR>\n" );
document.write( "========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );