document.write( "Question 287402: The hypotenuse of a right triangle is 16 inches longer than the shortest side and 8 inches longer than the remainig side. Find the dimensions of the triangle \n" ); document.write( "
Algebra.Com's Answer #208317 by ankor@dixie-net.com(22740)\"\" \"About 
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The hypotenuse of a right triangle is 16 inches longer than the shortest side and
\n" ); document.write( " 8 inches longer than the remaining side.
\n" ); document.write( "Find the dimensions of the triangle
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\n" ); document.write( "Let x = the hypotenuse
\n" ); document.write( "then
\n" ); document.write( "(x-16) = one side
\n" ); document.write( "and
\n" ); document.write( "(x-8) = remaining side
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\n" ); document.write( "Using pythag: a^2 + b^2 = x^2
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\n" ); document.write( "(x-16)^2 + (x-8)^2 = x^2
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 - 32x + 256 + x^2 - 16x + 64 = x^2
\n" ); document.write( "Combine like terms
\n" ); document.write( "x^2 + x^2 - x^2 - 32x - 16x + 256 + 64 = 0
\n" ); document.write( ":
\n" ); document.write( "x^2 - 48x + 320 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(x-40)(x-8) = 0
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\n" ); document.write( "x = 40, the hypotenuse (the only solution that will fit this problem)
\n" ); document.write( "then
\n" ); document.write( "40 - 16 = 24; one side
\n" ); document.write( "and
\n" ); document.write( "40 - 8 = 32; remaining side
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\n" ); document.write( "Check:
\n" ); document.write( "24^2 + 32^2 = 40^2
\n" ); document.write( "576 + 1024 = 1600 \n" ); document.write( "
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