document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287286>Question 287286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of angle A of a triangle is 20 degrees more than the measure of angle B. The measures of the angles are in a ratio of 3 to 4. Find the measure of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208236 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "1) a=b+20<BR>\n" );
document.write( "2) 3/4=b/a<BR>\n" );
document.write( "Only these two equations are needed<BR>\n" );
document.write( "3/4=b/(b+20)<BR>\n" );
document.write( "4b=3*(b+20)<BR>\n" );
document.write( "4b=3b+60<BR>\n" );
document.write( "b=60<BR>\n" );
document.write( "a=b+20=80<BR>\n" );
document.write( "a=80<BR>\n" );
document.write( "a+b+c=180<BR>\n" );
document.write( "a=80,b=60, c=40\r<BR>\n" );
document.write( "\n" );
document.write( "Curiously the relationship is not 3/4=a/b<BR>\n" );
document.write( "3/4=a/b<BR>\n" );
document.write( "a=b+20<BR>\n" );
document.write( "3/4=b+20/b<BR>\n" );
document.write( "3b=4*(b+20)<BR>\n" );
document.write( "3b=4b+80<BR>\n" );
document.write( "-80=b<BR>\n" );
document.write( "-60=a<BR>\n" );
document.write( "This way they have negative angles.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );