document.write( "Question 286995: A squire picture is mounted in a frame 1 cm wide. The area of the picture is 2/3 of the total area. Find the length of a side of the picture.
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Algebra.Com's Answer #208168 by ankor@dixie-net.com(22740)\"\" \"About 
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A square picture is mounted in a frame 1 cm wide.
\n" ); document.write( "The area of the picture is 2/3 of the total area.
\n" ); document.write( " Find the length of a side of the picture
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\n" ); document.write( "Let s = one side of the square picture
\n" ); document.write( "and
\n" ); document.write( "s^2 = area of picture
\n" ); document.write( "then
\n" ); document.write( "(s+2) = side including the frame
\n" ); document.write( "and
\n" ); document.write( "(s+2)^2 = overall area
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\n" ); document.write( "\"2%2F3\"(s+2)^2 = s^2
\n" ); document.write( "multiply both sides by 3
\n" ); document.write( "2(s+2)^2 = 3s^2
\n" ); document.write( "FOIL
\n" ); document.write( "2(s^2 + 4s + 4) = 3s^2
\n" ); document.write( "2s^2 + 8s + 8 = 3s^2
\n" ); document.write( "0 = 3s^2 - 2s^2 - 8s - 8
\n" ); document.write( "s^2 - 8s - 8 = 0
\n" ); document.write( "Use the quadratic formula to solve for s
\n" ); document.write( "Positive solution: s ~ 8.9 cm is the side of the picture
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\n" ); document.write( "Check this on calc
\n" ); document.write( "\"8.9%5E2%2F10.9%5E2\" = .666 ~ \"2%2F3\"\r
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