document.write( "Question 287104: how much of a 50% saline solution must be added to 100ml of 20% saline solution to make a mixture that is 40% saline?
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Algebra.Com's Answer #208165 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how much of a 50% saline solution must be added to 100ml of 20% saline solution to make a mixture that is 40% saline? \n" ); document.write( "--------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.20(100) + 0.50x = 0.40(100+x) \n" ); document.write( "Multiply thru by 100 and solve for \"x\": \n" ); document.write( "20*100 + 50x = 40*100 + 40x \n" ); document.write( "10x = 20*100 \n" ); document.write( "x = 200 ml (amt of 50% solution needed for the mixtue) \n" ); document.write( "========================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============================================== \n" ); document.write( " |