document.write( "Question 286912: Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)\r
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document.write( "A balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 48 feet above the ground. \r
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document.write( "(a) How many seconds after its release will the bag strike the ground? (Round your answer to two decimal places.)\r
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document.write( "(b) At what velocity will it strike the ground? (Round your answer to three decimal places.)\r
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Algebra.Com's Answer #208147 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.) \n" ); document.write( "A balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 48 feet above the ground. \n" ); document.write( "(a) How many seconds after its release will the bag strike the ground? (Round your answer to two decimal places.) \n" ); document.write( "(b) At what velocity will it strike the ground? (Round your answer to three decimal places.) \r \n" ); document.write( "\n" ); document.write( "a.) We can use the equation d = v(0) + (1/2)a*t^2 where v(0) is the initial velocity. In this case d = 48, v(0) = 0 and a = 32. Substitute these values and solve for t. \r \n" ); document.write( "\n" ); document.write( "b.) We can use the equation v(f) = v(0)+ a*t where v(f) is the final velocity and v(0) is the initial velocity. In this case v(0) = 0, a = 32. Substituting these values and the one calculated for t in part a.) you can calculate v(f) which is the velocity when the sandbag hits the ground. \n" ); document.write( " |