document.write( "Question 287050: I hope I can explain this right! I will post the problem, then what I need to do with it.\r
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document.write( "-12x+y=28\r
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document.write( "I need to find the ordered pair of the y-intercept and the x-intercept.
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document.write( "I just do not get how to figure these out!!!\r
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document.write( " Thanks in advance!!
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Algebra.Com's Answer #208136 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! The x-intercept is the value of x when the line crosses the x-axis which is when y = 0. So substitute 0 for y below and solve for x:\r \n" ); document.write( "\n" ); document.write( "-12x+y=28 \r \n" ); document.write( "\n" ); document.write( "-12x + 0 = 28 \n" ); document.write( "-12x = 28 \n" ); document.write( "x = -28/12 \n" ); document.write( "x = -7/3\r \n" ); document.write( "\n" ); document.write( "So the ordered pair for the x-intercept is y=0 and x=-7/3 or (-7/3,0).\r \n" ); document.write( "\n" ); document.write( "The y-intercept is the value of y when the line crosses the y-axis which is when x = 0. So substitute 0 for x below and solve for y:\r \n" ); document.write( "\n" ); document.write( "-12x+y = 28 \n" ); document.write( "-12*0 + y = 28 \n" ); document.write( "y = 28\r \n" ); document.write( "\n" ); document.write( "The ordered pair for the y-intercept then is ? \n" ); document.write( " |