document.write( "Question 287018: Will you please show detail of how this problem is solved and the correct answer? Thank you\r
\n" ); document.write( "\n" ); document.write( "A total of $15,000.00 was invested in two accounts, one at 4% and the other at 3% simple intrest. How much was invested in each account if the total earned was $550.00 per year?
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Algebra.Com's Answer #208113 by brucewill(101)\"\" \"About 
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Let x = the amount of 3% money
\n" ); document.write( "Then (15000-x) = the amount fo 4% money.
\n" ); document.write( "Interest = Principal * rate * time.\r
\n" ); document.write( "\n" ); document.write( "0.03x + 0.04x(15000-x) = 550
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\n" ); document.write( "0.03x + 600 - 0.04x = 550
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\n" ); document.write( "-0.01x = -50
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\n" ); document.write( "x = 5000 the amount of 3% money.
\n" ); document.write( "Therefore, 15000 - 5000 = 10000 the amount of 4% money.\r
\n" ); document.write( "\n" ); document.write( "Proof:
\n" ); document.write( "5000 * 3% = 150
\n" ); document.write( "10000 * 4% = 400, sums to 550.
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