document.write( "Question 287018: Will you please show detail of how this problem is solved and the correct answer? Thank you\r
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document.write( "A total of $15,000.00 was invested in two accounts, one at 4% and the other at 3% simple intrest. How much was invested in each account if the total earned was $550.00 per year? \n" );
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Algebra.Com's Answer #208113 by brucewill(101)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the amount of 3% money \n" ); document.write( "Then (15000-x) = the amount fo 4% money. \n" ); document.write( "Interest = Principal * rate * time.\r \n" ); document.write( "\n" ); document.write( "0.03x + 0.04x(15000-x) = 550 \n" ); document.write( "--- \n" ); document.write( "0.03x + 600 - 0.04x = 550 \n" ); document.write( "--- \n" ); document.write( "-0.01x = -50 \n" ); document.write( "=== \n" ); document.write( "x = 5000 the amount of 3% money. \n" ); document.write( "Therefore, 15000 - 5000 = 10000 the amount of 4% money.\r \n" ); document.write( "\n" ); document.write( "Proof: \n" ); document.write( "5000 * 3% = 150 \n" ); document.write( "10000 * 4% = 400, sums to 550. \n" ); document.write( " \n" ); document.write( " |