document.write( "Question 286994: The solution set of the equation square root x+6=x is \r
\n" ); document.write( "\n" ); document.write( "my answer was three. is this correct
\n" ); document.write( "Thank You
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Algebra.Com's Answer #208100 by richwmiller(17219)\"\" \"About 
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\"sqrt%28x%2B6%29=x\"
\n" ); document.write( "x+6=x^2
\n" ); document.write( "x^2-x-6=0
\n" ); document.write( "(x-3)(x+2) = 0
\n" ); document.write( "so 3 is one of the roots
\n" ); document.write( "Is -2 a usable root?
\n" ); document.write( "plug it back in the original
\n" ); document.write( "sqrt(-2+6)=-2
\n" ); document.write( "sqrt(4)=-2\r
\n" ); document.write( "\n" ); document.write( "Is that usable?
\n" ); document.write( "(-2)^2=4
\n" ); document.write( "(+2)^2=4
\n" ); document.write( "does +2=-2? no
\n" ); document.write( " does -2=-2? yes
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