document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286991>Question 286991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In rectangle ABCD, AB=(x-5y+94), BC= 3x+2y-82), CD= (4x-6y+55), and DA= (5x+4y-164). Find the perimeter of the rectangle. \r<BR>\n" );
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document.write( "Could you please help me on this problem?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208098 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the opposite sides of a parallelogram (rectangle) are equal<BR>\n" );
document.write( "___ this leaves you with a system of equations in x and y\r<BR>\n" );
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document.write( "x - 5y + 94 = 4x - 6y + 55 ___ 3x - y = 39\r<BR>\n" );
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document.write( "3x + 2y - 82 = 5x + 4y - 164 ___ 2x + 2y = 82 ___ x + y = 41 ___ y = 41 - x\r<BR>\n" );
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document.write( "substituting ___ 3x - (41 - x) = 39 ___ 4x = 80 ___ x = 20\r<BR>\n" );
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document.write( "substituting ___ y = 41 - (20) = 21\r<BR>\n" );
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document.write( "plug in the values for x and y to find the perimeter (sum of the sides) </SPAN>\n" );
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