document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286961>Question 286961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a triangle with given angles 135, and 30.  The side opposite the 135 degree angle is 12 units.  The questions is:  Find the length of the side opposite the 30 degree angle, x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208088 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> by the Law of Sines ___ x / 12 = [sin(30º)] / [sin(135º)]\r<BR>\n" );
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document.write( "x = 12 [sin(30º)] / [sin(135º)] </SPAN>\n" );
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