document.write( "Question 286903: 1/3+(-5/6)+(-1/2)=
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Algebra.Com's Answer #208045 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Take things one at a time. First, let's compute \"1%2F3%2B%28-5%2F6%29\". This is the same as \"1%2F3-5%2F6\"\r
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Solved by pluggable solver: Fractions Solver

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\n" ); document.write( " \"1%2F3-5%2F6\" Start with the given expression
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\n" ); document.write( " In order to subtract these two fractions, these fractions need to have a common denominator.
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\n" ); document.write( " In order to do that, we simply find that the LCM of 3 and 6 is 6 (note: if you need help with finding the LCM, check out this solver)
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\n" ); document.write( " Now we need to get each denominator to 6
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\n" ); document.write( " \"%282%2F2%29%281%2F3%29-5%2F6\" Multiply \"1%2F3\" by \"%282%2F2%29\"
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\n" ); document.write( " \"2%2F6-5%2F6\" Multiply \"1%2F3\" and \"%282%2F2%29\" to get \"2%2F6\"
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\n" ); document.write( " Since both fractions have a common denominator of 6, we can now combine the fractions
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\n" ); document.write( " \"%282-5%29%2F6\" Combine the fractions
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\n" ); document.write( " \"-3%2F6\" Subtract the numerators
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\n" ); document.write( " So
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\n" ); document.write( " \"1%2F3-5%2F6=-3%2F6\"
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\n" ); document.write( "\n" ); document.write( "Since \"1%2F3-5%2F6=-1%2F2\", the problem \"1%2F3%2B%28-5%2F6%29%2B%28-1%2F2%29\" simplifies to \"-1%2F2%2B%28-1%2F2%29\" (I replaced the first two terms with \"-1%2F2\")\r
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\n" ); document.write( "\n" ); document.write( "Now let's compute \"-1%2F2%2B%28-1%2F2%29\". This is the same as \"-1%2F2-1%2F2\"\r
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Solved by pluggable solver: Fractions Solver

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\n" ); document.write( " \"-1%2F2-1%2F2\" Start with the given expression
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\n" ); document.write( " Since both fractions have a common denominator of 2, we can now combine the fractions
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\n" ); document.write( " \"%28-1-1%29%2F2\" Combine the fractions
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\n" ); document.write( " \"-2%2F2\" Subtract the numerators
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\n" ); document.write( " So
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\n" ); document.write( " \"-1%2F2-1%2F2=-2%2F2\"
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\n" ); document.write( "\n" ); document.write( "note: \"-1%2F1=-1\"\r
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\n" ); document.write( "\n" ); document.write( "So \"-1%2F2%2B%28-1%2F2%29=-1\"\r
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\n" ); document.write( "\n" ); document.write( "So finally, this means that \"1%2F3%2B%28-5%2F6%29%2B%28-1%2F2%29=-1\" \n" ); document.write( "
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