document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286884>Question 286884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiator hold 15 liters.  How much pure antifreeze must be added to a mixture that is 10% antifreeze to make enough of a 25% mixture to fill the radiator? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208044 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of pure antifreeze that's added to the 10% mixture<BR>\n" );
document.write( "Then 15-x=amount of 10% antifreeze that is used\r<BR>\n" );
document.write( "\n" );
document.write( "Now we know that the amount of pure antifreeze in the in the antifreeze that's added (x) plus the amount of pure antifreeze in the 10% mixture(0.10(15-x)) has to equal the amount of pure antifreeze in the final mixture (0.25*15), so:\r<BR>\n" );
document.write( "\n" );
document.write( "x+0.10(15-x)=0.25*15<BR>\n" );
document.write( "x+1.5-0.10x=3.75<BR>\n" );
document.write( "0.90x=3.75-1.5<BR>\n" );
document.write( "0.90x=2.25<BR>\n" );
document.write( "x=2.5 liters-----------------amount of pure antifreeze needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "2.5+0.10(15-2.5)=0.25*15<BR>\n" );
document.write( "2.5+1.25=3.75<BR>\n" );
document.write( "3.75=3.75\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps----ptaylor\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );