document.write( "Question 286864: Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)\r
\n" ); document.write( "\n" ); document.write( "A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.)
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Algebra.Com's Answer #208019 by stanbon(75887)\"\" \"About 
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Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
\n" ); document.write( "A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.)
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\n" ); document.write( "h(t) = -16t^2 + 46t + 5
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\n" ); document.write( "Top of the arc is the vertex.
\n" ); document.write( "Vertex occurs when x = -b/2a = -46/(-32) = 23/16 seconds.
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\n" ); document.write( "Height at the vertex = h(23/16) = -16(23/16)^2+46(23/16)+5 = 38.06 ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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