document.write( "Question 286864: Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)\r
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document.write( "A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.)
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Algebra.Com's Answer #208019 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.) \n" ); document.write( "A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 46 feet per second. How high will the ball go? (Round your answer to two decimal places.) \n" ); document.write( "------------------ \n" ); document.write( "h(t) = -16t^2 + 46t + 5 \n" ); document.write( "--- \n" ); document.write( "Top of the arc is the vertex. \n" ); document.write( "Vertex occurs when x = -b/2a = -46/(-32) = 23/16 seconds. \n" ); document.write( "---- \n" ); document.write( "Height at the vertex = h(23/16) = -16(23/16)^2+46(23/16)+5 = 38.06 ft. \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |