document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286815>Question 286815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the amount owed at the end of 7 years if 2700 is loaned at a rate 8% compounded quarterly.<BR>\n" );
document.write( "A=p(1+r/n)^nt<BR>\n" );
document.write( "A=28(1+.08/2700)^2700*7<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207989 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the amount owed at the end of 7 years if 2700 is loaned at a rate 8% compounded quarterly.<BR>\n" );
document.write( "A=p(1+r/n)^nt<BR>\n" );
document.write( "8% per year is 2% per quarter<BR>\n" );
document.write( "n = 4<BR>\n" );
document.write( "t = 7<BR>\n" );
document.write( "r = 0.08<BR>\n" );
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document.write( "A = 2700*(1 + 0.02)^28<BR>\n" );
document.write( "A =~ 4700.77<BR>\n" );
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