document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286815>Question 286815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the amount owed at the end of 7 years if 2700 is loaned at a rate 8% compounded quarterly.<BR>\n" );
document.write( "A=p(1+r/n)^nt<BR>\n" );
document.write( "A=28(1+.08/2700)^2700*7<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207986 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=P((1+(R/N))^(NT))<BR>\n" );
document.write( "P is initial capital<BR>\n" );
document.write( "A is accumulated capital<BR>\n" );
document.write( "R is yearly rate<BR>\n" );
document.write( "N is number of payments per year<BR>\n" );
document.write( "T is term (number of years over which compounded) <BR>\n" );
document.write( "p=2700<BR>\n" );
document.write( "n=4<BR>\n" );
document.write( "t=7<BR>\n" );
document.write( "r=.08<BR>\n" );
document.write( "plug those in and try again </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );