document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286773>Question 286773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A random sample of 30 women drank an average of 15 cups of coffee per week, with the sample standard deviation equals to 3 cups. A upper limit of an approximate confidence interval with 95% of the population avg cup drunk is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207942 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A random sample of 30 women drank an average of 15 cups of coffee per week, with the sample standard deviation equals to 3 cups. A upper limit of an approximate confidence interval with 95% of the population avg cup drunk is?<BR>\n" );
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document.write( "sample mean = 15<BR>\n" );
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document.write( "standard error = E = t*s/sqrt(n)<BR>\n" );
document.write( "E = invT(97.5 with df = 29)(3/sqrt(30)] = 2.0452*3/sqrt(30) = 1.1202<BR>\n" );
document.write( "---<BR>\n" );
document.write( "95% CI: 15-1.1202 < u < 15+1.1202<BR>\n" );
document.write( "95% CI: 13.880 < u < 16.120<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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