document.write( "Question 286594: A rectangular garden is enclosed so that the river borders 1 side and 300m of fencing are used for the other 3 sides.\r
\n" ); document.write( "\n" ); document.write( "a)What is the formula for the area in terms of x and y?
\n" ); document.write( "b)What is the formul that relates x and y to the perimeter?
\n" ); document.write( "c)Write a formulaa for the area in terms of x only
\n" ); document.write( "d)What are the dimensions of the garden if the area is a maximum?
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Algebra.Com's Answer #207878 by josmiceli(19441)\"\" \"About 
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Let the length of the side bordering the river = \"y\"
\n" ); document.write( "Let the 2 sides perpendicular to the side bordering the river = \"x\"
\n" ); document.write( "given:
\n" ); document.write( "a)\"A+=+xy\" m2
\n" ); document.write( "\"P+=+300+%2B+y\"
\n" ); document.write( "b)\"P=+2x+%2B+2y\" m
\n" ); document.write( "----------------
\n" ); document.write( "\"2x+=+300+-+y\"
\n" ); document.write( "\"y+=+300+-+2x\"
\n" ); document.write( "\"A+=+x%2A%28300+-+2x%29\"
\n" ); document.write( "c)\"A+=+300x+-+2x%5E2\"
\n" ); document.write( "\"x\" is a maximum halfway between the 2 roots. First I'll find the roots
\n" ); document.write( "\"x%2A%282x+-+300%29+=+0\"
\n" ); document.write( "The roots are \"x+=+0\" and
\n" ); document.write( "\"2x+-+300+=+0\"
\n" ); document.write( "\"2x+=+300\"
\n" ); document.write( "\"x+=+150\"
\n" ); document.write( "The midpoint is \"x+=+75\"
\n" ); document.write( "\"y+=+300+-+2x\"
\n" ); document.write( "\"y+=+300+-+150\"
\n" ); document.write( "\"y+=+150\"
\n" ); document.write( "d)The dimensions that maximize area are 75 x 150
\n" ); document.write( "check:
\n" ); document.write( "Just vary the dimensions a little bit, and Area should decrease
\n" ); document.write( "\"A+=+75%2A150\"
\n" ); document.write( "\"A+=+11250\" m2
\n" ); document.write( "Suppose:
\n" ); document.write( "\"A2+=+76%2A148\" -note that \"2%2A76+%2B+148+=+152+%2B+148\"
\n" ); document.write( "and \"152%2B+148+=+300\" as it should
\n" ); document.write( "\"A2+=+11248\" It decreased by \"2\" m
\n" ); document.write( "OK
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