document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286595>Question 286595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y varies inversely as x is squared. Y is 25 when x is 2. Find y when x is 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207875 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean y is inversely related to x squared:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+k%2Fx%5E2 ALIGN=MIDDLE  ALT=\"y+=+k%2Fx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Find k<BR>\n" );
document.write( "25 = k/4<BR>\n" );
document.write( "k = 100<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "at x = 5:<BR>\n" );
document.write( "y = 100/25 = 4\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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