document.write( "Question 286420: An Investment of $4400.00 is made into a 10.5% annual simple interest account. How much money is deposited into an 8% annual simple interest account if the total annual, interest earned on both accounts is 9% of the total investment. \n" ); document.write( "
Algebra.Com's Answer #207871 by checkley77(12844)\"\" \"About 
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.105X+.08(4400-X)=4400*.09
\n" ); document.write( ".105X+352-.08X=396
\n" ); document.write( ".025X=396-352
\n" ); document.write( ".025X=44
\n" ); document.write( "X=44/.025
\n" ); document.write( "X=1,760 AMOUNT INVESTED @ 10.5%
\n" ); document.write( "4,400-1,760=2,640 AMOUNT INVESTED @ 8%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".105*1,760+.08*2,640=4,400*.09
\n" ); document.write( "184.8+211.2=396
\n" ); document.write( "396=396
\n" ); document.write( "
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