document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286572>Question 286572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a cake has three circular tires; each is 8 cm high. the tiers have diameters 60 cm, 48 cm, 36 cm.  what is the surface area to be covered by frosting? there is no frosting between layers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207858 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The surface area of a circle is given by A = 4pi(r^2), where pi = 3.14.\r<BR>\n" );
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document.write( "The cake with diameter 60cm has a radius of 30cm.\r<BR>\n" );
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document.write( "The cake with diameter 48cm has a radius of 24cm.\r<BR>\n" );
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document.write( "The cake with diameter 36cm has a radius of 18cm.\r<BR>\n" );
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document.write( "What do you think can be done with this information to find the total surface area?\r<BR>\n" );
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document.write( "You need to use the formula above 3 times (one for each cake tire).\r<BR>\n" );
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document.write( "Total frosting on cake = 4(3.14)(30cm)^2 + 4(3.14)(24cm)^2 + 4(3.14)(18cm)^2\r<BR>\n" );
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document.write( "You can take it from here.\r<BR>\n" );
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