document.write( "Question 286505: the width of rectangle is 5 feet and the diagonal is 9 feet. what is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #207802 by texttutoring(324)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "You can make a right triangle with the diagonal of the rectangle and its width.\r
\n" ); document.write( "\n" ); document.write( "diagonal = 9
\n" ); document.write( "width = 5\r
\n" ); document.write( "\n" ); document.write( "use Pythagorean theorem to solve for the unknown side, the length:\r
\n" ); document.write( "\n" ); document.write( "9^2 = 5^2 + l^2
\n" ); document.write( "81-25 = l^2
\n" ); document.write( "l= Sqrt(56)
\n" ); document.write( "l = 7.48\r
\n" ); document.write( "\n" ); document.write( "The area is A=l*w\r
\n" ); document.write( "\n" ); document.write( "A= 7.48 * 5
\n" ); document.write( "A= 37.4
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