document.write( "Question 286499: 1.Jill combines 10% fruit juice with PURE fruit juice to make 2 liters of 25% fruit juice. How much pure fruit juice does she use in the mix?\r
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\n" ); document.write( "\n" ); document.write( "NOTE:( can you please show the work or somehow explain them so i can understand how to do it..thank you)
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Algebra.Com's Answer #207798 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1.Jill combines 10% fruit juice with PURE fruit juice to make 2 liters of 25% fruit juice. How much pure fruit juice does she use in the mix?
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\n" ); document.write( "Equation:
\n" ); document.write( "Solution using 2 variable:
\n" ); document.write( "Let x be amount of 10% juice
\n" ); document.write( "Let y = amount of 100% juice
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\n" ); document.write( "Quantity Equation: x + y = 2 liters
\n" ); document.write( "Pure juice Equations: 0.10x + 1.00y = 0.25*2
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\n" ); document.write( "Multiply thru 1st equation by 10
\n" ); document.write( "Multiply thru 2nd equation by 100
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\n" ); document.write( "10x + 10y = 20
\n" ); document.write( "10x + 100y = 25*2
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\n" ); document.write( "Subtract 1st equation from 2nd and solve for \"y\":
\n" ); document.write( "90y = 30
\n" ); document.write( "y = 1/3 liter (amount of pure fruit juice needed for the mixture)
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\n" ); document.write( "Solution using 1 variable:
\n" ); document.write( "Let x be amount of 10% juice.
\n" ); document.write( "Then 2-x is amount of 100% juice
\n" ); document.write( "pure + pure = pure
\n" ); document.write( "0.10x + 1(2-x) = 0.25*2
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "10x + 100(2-x) = 25*2
\n" ); document.write( "10x + 200-100x = 50
\n" ); document.write( "-90x = -150
\n" ); document.write( "x = 15/9
\n" ); document.write( "x = 5/3 liter
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\n" ); document.write( "2-(5/3) = 1/3 liter (amount of pure fruit juice needed for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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