document.write( "Question 286498: In what ratio should a 20% methyl alcohol solution be mixed with a 50% methyl alcohol solution so that the resultant solution has 40% methyl alcohol in it? \n" ); document.write( "
Algebra.Com's Answer #207793 by richwmiller(17219)\"\" \"About 
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you are mixing two solutions to get a third.
\n" ); document.write( "so a+b=c
\n" ); document.write( "we don't know how much to mix nor how much we will end up with.
\n" ); document.write( "so we call the amount to mix x and y and the total will of course be x+y\r
\n" ); document.write( "\n" ); document.write( ".2x+.5y=.4(x+y)
\n" ); document.write( "2x+5y=4(x+y)
\n" ); document.write( "2x+5y=4x+4y
\n" ); document.write( "2x+y=4x
\n" ); document.write( "y=2x
\n" ); document.write( "so you will mix 2x for every y
\n" ); document.write( "y/x=2
\n" ); document.write( "x/y=1/2
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