document.write( "Question 286498: In what ratio should a 20% methyl alcohol solution be mixed with a 50% methyl alcohol solution so that the resultant solution has 40% methyl alcohol in it? \n" ); document.write( "
Algebra.Com's Answer #207793 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! you are mixing two solutions to get a third. \n" ); document.write( "so a+b=c \n" ); document.write( "we don't know how much to mix nor how much we will end up with. \n" ); document.write( "so we call the amount to mix x and y and the total will of course be x+y\r \n" ); document.write( "\n" ); document.write( ".2x+.5y=.4(x+y) \n" ); document.write( "2x+5y=4(x+y) \n" ); document.write( "2x+5y=4x+4y \n" ); document.write( "2x+y=4x \n" ); document.write( "y=2x \n" ); document.write( "so you will mix 2x for every y \n" ); document.write( "y/x=2 \n" ); document.write( "x/y=1/2 \n" ); document.write( " \n" ); document.write( " |