document.write( "Question 286501: How do I simplify $\"+root%283%2C54c%5E4%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #207792 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+root%283%2C54c%5E4%29+\"$ Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( " $\"+root%283%2C2%2A27%2Ac%5E3%2Ac%29+\"$ Factor 54 into 2*27 (note how 27 is a perfect cube) and factor $\"c%5E4\"$ into $\"c%5E3%2Ac\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"+root%283%2C2%29%2Aroot%283%2C27%29%2Aroot%283%2Cc%5E3%29%2Aroot%283%2Cc%29+\"$ Break up the root.\r
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\n" ); document.write( "\n" ); document.write( " $\"+root%283%2C2%29%2A3%2Ac%2Aroot%283%2Cc%29+\"$ Take the cube root of 27 to get 3. Take the cube root of $\"c%5E3\"$ to get $\"c\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"+3c%2Aroot%283%2C2c%29+\"$ Rearrange the terms and combine the roots.\r
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\n" ); document.write( "\n" ); document.write( "So $\"+root%283%2C54c%5E4%29+=+3c%2Aroot%283%2C2c%29+\"$ \n" ); document.write( "

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