document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286483>Question 286483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide. its perimeter is 48cm find its dimension. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207776 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l = length, w=width\r<BR>\n" );
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document.write( "l=2w (because the length is twice as long as the width)\r<BR>\n" );
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document.write( "The perimeter can be expressed by:\r<BR>\n" );
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document.write( "P=2w+2l\r<BR>\n" );
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document.write( "Substitute P=48 and l=2w into the equation:\r<BR>\n" );
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document.write( "48 = 2w + 2(2w)<BR>\n" );
document.write( "48 = 2w + 4w<BR>\n" );
document.write( "48 = 6w<BR>\n" );
document.write( "w=8\r<BR>\n" );
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document.write( "The width is 8cm and the length is 16cm. </SPAN>\n" );
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