document.write( "Question 286464: Juan left home on his bicycle at 10:00 a.m. traveling at 21 km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63 km/h, what time did Juan's brother overtake him?\r
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Algebra.Com's Answer #207770 by texttutoring(324)![]() ![]() You can put this solution on YOUR website! Let Vb=velocity of the bike=21km/h \n" ); document.write( " Vm=velocity of the motorcycle = 63km/h\r \n" ); document.write( "\n" ); document.write( "The distances they travel are equal, because it's the same route and they left from the same place. We know the equation D=VT, where D=distance, V=velocity and T=time. Because the distances for the motorcycle and bike are the same, we can just set them equal to each other:\r \n" ); document.write( "\n" ); document.write( "D=D \n" ); document.write( "Vb*Tb = Vm*Tm\r \n" ); document.write( "\n" ); document.write( "The time the motorcycle travels is 2 hours less than the time the bike travels, so Tm=Tb-2\r \n" ); document.write( "\n" ); document.write( "Vb*Tb = Vm(Tm-2) \n" ); document.write( "21Tb = 63(Tb-2) \n" ); document.write( "126 = 42Tb \n" ); document.write( "Tb=3\r \n" ); document.write( "\n" ); document.write( "The bike travels for 3 hours. The motorcycle travels for 2 hours less, so 1 hour. They meet at 1:00pm. \n" ); document.write( " |