document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286451>Question 286451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 60% of all woman work outside the home. In a random sample of 20 woman what is the probability that:\r<BR>\n" );
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document.write( "a. exactly 15 are employed<BR>\n" );
document.write( "b. at least 10 are employed<BR>\n" );
document.write( "c. at most 5 are not employed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207757 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 60% of all woman work outside the home. In a random sample of 20 woman what is the probability that:<BR>\n" );
document.write( "Binomial Problem with n = 20 ; p = 0.6<BR>\n" );
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document.write( "a. exactly 15 are employed<BR>\n" );
document.write( "P(x = 15) = 20C15(0.6)^15*(0.4)^5 = 0.0746...<BR>\n" );
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document.write( "b. at least 10 are employed<BR>\n" );
document.write( "P(10<= x <=15) = 1 - binomcdf(20,0.6,9) = 0.8725<BR>\n" );
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document.write( "c. at most 5 are not employed<BR>\n" );
document.write( "P(not employed) = 0.4<BR>\n" );
document.write( "P(0<= x <=5) = binomcdf(20,0.4,5) = 0.1256<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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