document.write( "Question 286434: i must solve for x logx32=5 how do you do this the x is little \n" ); document.write( "

Algebra.Com's Answer #207744 by jim_thompson5910(35256) $\"\"$ $\"About$

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Recall that $\"log%28b%2C%28x%29%29=y\"$ can be rewritten as $\"b%5Ey=x\"$ . In this case, this means that $\"log%28x%2C%2832%29%29=5\"$ can be rewritten as $\"x%5E5=32\"$ . Also, take note that $\"32=2%5E5\"$ . So $\"x%5E5=2%5E5\"$ which means that $\"x=2\"$ (take the 5th root of both sides) \n" ); document.write( "

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