document.write( "Question 286372: tom leaves school on a bike going 10 mph. zeke leaves school 1 hour later going the same direction at a rate of 30 mph. how long before zeke overtakes tom? \n" ); document.write( "
Algebra.Com's Answer #207685 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=10T FOR TOM. \n" ); document.write( "D=30(T-1) FOR ZEKE. \n" ); document.write( "SET THESE 2 EQUATIONS EQUAL: \n" ); document.write( "10T=30(T-1) \n" ); document.write( "10T=30T-30 \n" ); document.write( "10T-30T=-30 \n" ); document.write( "-20T=-30 \n" ); document.write( "T=-30/-20 \n" ); document.write( "T=1.5 HOURS THEY WILL MEET. \n" ); document.write( "PROOF: \n" ); document.write( "10*1.5=30(1.5-1) \n" ); document.write( "15=30*.5 \n" ); document.write( "15=15 \n" ); document.write( " |