document.write( "Question 286372: tom leaves school on a bike going 10 mph. zeke leaves school 1 hour later going the same direction at a rate of 30 mph. how long before zeke overtakes tom? \n" ); document.write( "
Algebra.Com's Answer #207685 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=10T FOR TOM.
\n" ); document.write( "D=30(T-1) FOR ZEKE.
\n" ); document.write( "SET THESE 2 EQUATIONS EQUAL:
\n" ); document.write( "10T=30(T-1)
\n" ); document.write( "10T=30T-30
\n" ); document.write( "10T-30T=-30
\n" ); document.write( "-20T=-30
\n" ); document.write( "T=-30/-20
\n" ); document.write( "T=1.5 HOURS THEY WILL MEET.
\n" ); document.write( "PROOF:
\n" ); document.write( "10*1.5=30(1.5-1)
\n" ); document.write( "15=30*.5
\n" ); document.write( "15=15
\n" ); document.write( "
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