document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34458>Question 34458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20764 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the Local train is x mph<BR>\n" );
document.write( "AT x mph, the Local train takes 50/x hours to travel 50 miles;<BR>\n" );
document.write( "The speed of the Express train is 2x mph;<BR>\n" );
document.write( "The Express train takes 50/2x (25/x) hours to travel 50 miles;<BR>\n" );
document.write( "Hours taken by the Local train = Hours taken by the Express train + 1<BR>\n" );
document.write( "=> 50/x = 25/x + 1<BR>\n" );
document.write( "=> 50/x - 25/x = 1<BR>\n" );
document.write( "=> 25/x = 1<BR>\n" );
document.write( "=> x = 25;<BR>\n" );
document.write( "The local train travels at 25 mph and the Express train at 50 mph. </SPAN>\n" );
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