document.write( "Question 286298: A college student earned $6300 during summer vacation working as a waiter in a popular restaurant. The student invested part of the money at 8% and the rest at 7%. If the student received a total of $479 in interest at the end of the year, how much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #207616 by stanbon(75887)\"\" \"About 
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A college student earned $6300 during summer vacation working as a waiter in a popular restaurant. The student invested part of the money at 8% and the rest at 7%. If the student received a total of $479 in interest at the end of the year, how much was invested at 8%?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Equation: x + y = 6300
\n" ); document.write( "Interest Equation:0.08x + 0.07y = 479
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\n" ); document.write( "Multiply thru the 1st equation by 7
\n" ); document.write( "Multiply thru the 2nd equation by 100
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\n" ); document.write( "7x + 7y = 7*6300
\n" ); document.write( "8x + 7y = 47900
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\n" ); document.write( "Subtract 1st Eq from 2nd and solve for \"x\":
\n" ); document.write( "x = $3800 (amt. invested at 8%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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