document.write( "Question 286296: Use the elimination method to solve system equation:
\n" ); document.write( "6x-y=36
\n" ); document.write( "6y=6x-66 \n" ); document.write( "

Algebra.Com's Answer #207614 by oberobic(2304) $\"\"$ $\"About$

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The 'elimination' method could just as well be called the 'addition' method: you manipulate the equations until you add them to eliminate one unknown. Then use substitution to find the other unknown.
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\n" ); document.write( "6x - y = 36
\n" ); document.write( "6y = 6x - 66
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\n" ); document.write( "The second equation must be rearranged.
\n" ); document.write( "Subtract 6x from both sides.
\n" ); document.write( "-6x + 6y = -66
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\n" ); document.write( "The terms 6x and -6x would eliminate the 'x' values, allowing you to solve the 'y' values.
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\n" ); document.write( "6x - y = 36
\n" ); document.write( "-6x + 6y = -66
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\n" ); document.write( "Adding them.
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\n" ); document.write( "5y = -30
\n" ); document.write( "y = -6
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\n" ); document.write( "Substituting y = -6.
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\n" ); document.write( "6x -(-6) = 36
\n" ); document.write( "6x + 6 = 36
\n" ); document.write( "6x = 30
\n" ); document.write( "x = 5
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\n" ); document.write( "Check by substituting x=5 and y=-6 into the second equation.
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\n" ); document.write( "6y = 6x - 66
\n" ); document.write( "6(-6) = 6(5) -66
\n" ); document.write( "-36 = 30-66
\n" ); document.write( "-36 = -36
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer:
\n" ); document.write( "x = 5
\n" ); document.write( "y = -6
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\n" ); document.write( "Done. \n" ); document.write( "

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