document.write( "Question 4438: I think I know the answer, but I need to know if I'm right: Brian leaves Eagle Nest Campground at 8:30 am, and hikes along a trail at 4kph. One hour later, Rob leaves the same campground and hikes along the same trail at 6 kph. At what time of day will he catch up with Brian? (I think that they meet at 2:30 pm. Am I correct, if not can you help me figure out where I went wrong?) Thanks \n" ); document.write( "
Algebra.Com's Answer #2076 by pushpaharan(47)![]() ![]() ![]() You can put this solution on YOUR website! at the time of both mee they would have travelled same distance and meet at same time. \n" ); document.write( "let it be x \n" ); document.write( "time = distance / speed\r \n" ); document.write( "\n" ); document.write( "time taken by Brian = x/ 4\r \n" ); document.write( "\n" ); document.write( "time taken by Rob = x/6 \n" ); document.write( "x/4 - x/6 = 1 \n" ); document.write( "3x/12 - 2x/12 = 1 \n" ); document.write( "x =12\r \n" ); document.write( "\n" ); document.write( "to travel 12 miles it takes 3 hrs for Brian (12/4)\r \n" ); document.write( "\n" ); document.write( "they will meet at 11.30 am \n" ); document.write( " |