document.write( "Question 34483: A man has 3 times as much money invested in 12% bonds as he has in stocks paying 9%. If his yearly income from the investments is $2,700, what is his total investment is? \n" ); document.write( "
Algebra.Com's Answer #20759 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let amount invested at 9% be \"x\" \n" ); document.write( "Interest on this amount is 0.09x dollars \n" ); document.write( "Amount invested at 12% is \"3x\" \n" ); document.write( "Interest on this amount is 0.12(3x)=0.36x dollars \n" ); document.write( "EQUAITON: \n" ); document.write( "Interest + interext = 2700 dollars \n" ); document.write( "0.09x + 0.36x=2700 \n" ); document.write( "9x +36x=270000 \n" ); document.write( "45x=270000 \n" ); document.write( "x=6000 (amount invested at 9%) \n" ); document.write( "Total investment is x+3x=4x=4(6000)=$24000.00 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |