document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286260>Question 286260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to write this rational expression in its lowest term:\r<BR>\n" );
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document.write( "8x squared - 10x - 3 over<BR>\n" );
document.write( "8x squared -  6x - 9\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207572 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (8x^2 - 10x - 3)/(8x^2 - 6x - 9) =\r<BR>\n" );
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document.write( "((4x+1)*(2x-3))/((4x+3)*(2x-3)) =\r<BR>\n" );
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document.write( "(4x+1)/(4x+3)   \r<BR>\n" );
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document.write( "*Note that (2x-3)/(2x-3) = 1 so those terms cancelled out. </SPAN>\n" );
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