document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286256>Question 286256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really don't even know where to begin with this problem.<BR>\n" );
document.write( "Let 2^a = 5 and 2^b = 7. Using exponent rules, solve the equation in terms of a and b. <BR>\n" );
document.write( "0.4^x=343 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207571 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 2^a = 5 and 2^b = 7. Using exponent rules, solve the equation in terms of a and b. <BR>\n" );
document.write( "0.4^x=343<BR>\n" );
document.write( "[2^2/2*5]^x = 7^3<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "Rewrite in terms of a and b:<BR>\n" );
document.write( "(2^2/(2*2^a))^x = (2^b)^3<BR>\n" );
document.write( "(2^2/2(a+1))^x = 2^(3b)<BR>\n" );
document.write( "(2^(1-a))^x = 2^(3b)<BR>\n" );
document.write( "(2^(x(1-a)) = 2^3b<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Equate the exponents and solve for \"x\":<BR>\n" );
document.write( "x(1-a) = 3b<BR>\n" );
document.write( "x = (3b)/(1-a)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "======================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );