document.write( "Question 286180: Jessica is 24 years old. She is twice as old as Jane was when Jessica was as old as Jane is now.
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Algebra.Com's Answer #207510 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x = Jane's age now.\r\n" );
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document.write( "Jane was 12 when Jessica was Jane's present age, x.\r\n" );
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document.write( "Let y = the number of years ago it's been since Jane was 12\r\n" );
document.write( "and Jessica was x. \r\n" );
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document.write( "Jessica's age y years ago = Jane's age now.\r\n" );
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document.write( "                   24 - y = x\r\n" );
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document.write( "   Jane's age y years ago = 12\r\n" );
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document.write( "                    x - y = 12\r\n" );
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document.write( "So we have this system:\r\n" );
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document.write( "\"system%2824-y=x%2C+x-y=12%29\"\r\n" );
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document.write( "Can you solve that system?  If not post again asking how,\r\n" );
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document.write( "x=18, y=6\r\n" );
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document.write( "So Jane is 18 years old now.  \r\n" );
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document.write( "Checking:  y=6 years ago, Jane was 12, and Jessica was 18. Today\r\n" );
document.write( "Jessica is twice 12, Jane's age then.\r\n" );
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document.write( "Edwin
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