document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=286109>Question 286109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of a tea shop wants to mix three kinds of tea to make 100oz of a mixture that will sell for $0.83 per oz.  He uses Orange Pekoe, which sells for $0.80 per oz, Irish Breakfast, for $0.85 per oz, and Earl Grey which sells for $0.95 per oz.  If he wants to use twice as much Orang Pekoe as Irish Breakfast, how much of each kind of tea should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207486 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The owner of a tea shop wants to mix three kinds of tea to make 100oz of a<BR>\n" );
document.write( " mixture that will sell for $0.83 per oz.<BR>\n" );
document.write( " He uses Orange Pekoe, which sells for $0.80 per oz, Irish Breakfast, for $0.85<BR>\n" );
document.write( " per oz, and Earl Grey which sells for $0.95 per oz. <BR>\n" );
document.write( "If he wants to use twice as much Orange Pekoe as Irish Breakfast, how much of <BR>\n" );
document.write( "each kind of tea should be used?<BR>\n" );
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document.write( "Let x = amt of Irish breakfast tea required<BR>\n" );
document.write( "It says,\"use twice as much Orange Pekoe as Irish Breakfast\", therefore:<BR>\n" );
document.write( "2x = amt of Orange Pekoe Tea<BR>\n" );
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document.write( "Let y = amt of Earl Grey<BR>\n" );
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document.write( "Amt of tea equation<BR>\n" );
document.write( "x + 2x + y = 100 oz<BR>\n" );
document.write( "3x + y = 100<BR>\n" );
document.write( "y = (100-3x)<BR>\n" );
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document.write( "Cost of tea equation<BR>\n" );
document.write( ".85x + .80(2x) + .95y = .83(100)<BR>\n" );
document.write( ".85x + 1.60x + .95y = 83<BR>\n" );
document.write( "2.45x + .95y = 83<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Replace y with (100-3x)<BR>\n" );
document.write( "2.45x + .95(100-3x) = 83<BR>\n" );
document.write( "2.45x + 95 - 2.85x = 83<BR>\n" );
document.write( "2.45x - 2.85x = 83 - 95<BR>\n" );
document.write( "-.40x = -12<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-12%29%2F%28-.4%29 ALIGN=MIDDLE  ALT=\"%28-12%29%2F%28-.4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 30 oz of Irish Tea required<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2(30) = 60 oz of Orange Pekoe<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y = 100 - 90<BR>\n" );
document.write( "y = 10 oz of Earl Grey<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check solution in cost equation<BR>\n" );
document.write( ".85(30) + .80(60) + .95(10) = .83(100)<BR>\n" );
document.write( "25.5 + 48.0 + 9.5 = 83<BR>\n" );
document.write( " </SPAN>\n" );
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