document.write( "Question 286156: A rectangle has an area of 60 square meters and a perimeter of 38 meters. find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #207485 by checkley77(12844) $\"\"$ $\"About$

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XY=60 OR X=60/Y
\n" ); document.write( "2X+2Y=38
\n" ); document.write( "2(60/Y)+2Y=38
\n" ); document.write( "120/Y+2Y=38
\n" ); document.write( "(120+2Y*Y)/Y=38
\n" ); document.write( "(120+2Y^2)/Y=38
\n" ); document.write( "120+2Y^2=38Y
\n" ); document.write( "2Y^2-38Y+120=0
\n" ); document.write( "2(Y^2-19Y+60)=0
\n" ); document.write( "2(Y-15)(Y-4)=0
\n" ); document.write( "Y-15=0
\n" ); document.write( "Y=15 ANS
\n" ); document.write( "Y-4=0
\n" ); document.write( "Y=4 ANS.
\n" ); document.write( "X*4=60
\n" ); document.write( "X=60/4
\n" ); document.write( "X=15 ANS
\n" ); document.write( "X*15=60
\n" ); document.write( "X=60/15
\n" ); document.write( "X=4 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*15+2*4=38
\n" ); document.write( "30+8=38
\n" ); document.write( "38=38 \n" ); document.write( "

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