document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34331>Question 34331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x^3y+20x^2y^2+20xy^3<BR>\n" );
document.write( "all over<BR>\n" );
document.write( "5xy\r<BR>\n" );
document.write( "\n" );
document.write( "please simplify\r<BR>\n" );
document.write( "\n" );
document.write( "note:^ means raised to the power of. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20748 by </B><A HREF=/tutors/aboutme.mpl?userid=benni1013><B>benni1013(206)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benni1013><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When dividing a trinomial by a monomial the best way is to divide and conquer.<BR>\n" );
document.write( "Subtract the powers in this case.\r<BR>\n" );
document.write( "\n" );
document.write( "Also anything to the 0 power is one. Anything multiply by one is itself\r<BR>\n" );
document.write( "\n" );
document.write( "(5x^3y/5xy)+20x^2y^2/5xy+20xy^3/5xy==>x^2+4xy+4y^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );