document.write( "Question 286104: ok my teacher gave us words problmes to do and im stuck. Here is the problem: Bill is 3 times as old as Peter. Six years from now, Bill will be twice as old as Peter will be then. Find their present ages. Im stuck on what the formula is. \n" ); document.write( "
Algebra.Com's Answer #207454 by stanbon(75887)\"\" \"About 
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Bill is 3 times as old as Peter.
\n" ); document.write( "b = 3p
\n" ); document.write( "-------------------
\n" ); document.write( "Six years from now, Bill will be twice as old as Peter will be then.
\n" ); document.write( "(b+6) = 2(p+6)
\n" ); document.write( "---------------------------
\n" ); document.write( "Substitute for \"b\" and solve for \"p\":
\n" ); document.write( "(3p+6) = 2(p+6)
\n" ); document.write( "3p+6 = 2p+12
\n" ); document.write( "p = 6 (peter's age now)
\n" ); document.write( "---
\n" ); document.write( "Since b = 3p,
\n" ); document.write( "b = 18 (bill'e age now)
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Find their present ages.
\n" ); document.write( "
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