document.write( "Question 286065: A father is twice a old as his son is today. A few years back, he was thrice as old and half that number of years prior to that, he was 5 times as old; and 6 years before that, he was as old as his son is today. The father age is (in yrs) \n" ); document.write( "
Algebra.Com's Answer #207452 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=son's age today
\n" ); document.write( "Then 2x=father's age today
\n" ); document.write( "t years back, we have:
\n" ); document.write( "x-t=son's age t years back
\n" ); document.write( "2x-t=father's age t years back and we are told:
\n" ); document.write( "2x-t=3(x-t)=
\n" ); document.write( "2x-t=3x-3t
\n" ); document.write( "x=2t-----------------------eq1
\n" ); document.write( "t/2 years before this we have:
\n" ); document.write( "x-t-t/2=x-3t/2=son's age half that number of years before that
\n" ); document.write( "2x-3t/2=father's age half that number of years before that and we are told:
\n" ); document.write( "2x-3t/2=5(x-3t/2)=
\n" ); document.write( "2x-3t/2=5x-15t/2 multiply each term by 2
\n" ); document.write( "4x-3t=10x-15t
\n" ); document.write( "12t=6x
\n" ); document.write( "or
\n" ); document.write( "x=2t or t=x/2 same as before----------------------eq2\r
\n" ); document.write( "\n" ); document.write( "6 years before this
\n" ); document.write( "x-(3t/2)-6=son's age
\n" ); document.write( "2x-(3t/2)-6=fathers age and we are told that:
\n" ); document.write( "2x-(3t/2)-6=x---------------eq3 multiply each term by 2
\n" ); document.write( "4x-3t-12=2x
\n" ); document.write( "2x-3t=12--------------eq3
\n" ); document.write( "substitute t=x/2 in eq3
\n" ); document.write( "2x-3(x/2)=12 multiply each term by 2
\n" ); document.write( "4x-3x=24
\n" ); document.write( "x=24---------son's age now
\n" ); document.write( "t=x/2=12 years
\n" ); document.write( "2x=2*24=48----father's age now
\n" ); document.write( "CK
\n" ); document.write( "12 years ago:
\n" ); document.write( "son was 24-12=12
\n" ); document.write( "father was 48-12=36 or 3*12
\n" ); document.write( "6 years prior to that:
\n" ); document.write( "son was 12-6=6
\n" ); document.write( "father36-6=30 or 5*6
\n" ); document.write( "6 years prior to that:
\n" ); document.write( "father was 30-6=24 same as son's age now\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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