document.write( "Question 286016: Some friends on a hike leave at 9am and return at 2pm. They spend one-quarter of the total distance walking uphill, one-half walking on level ground, and one-quarter walking downhill. if their speed is 4mph on level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk?\r
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document.write( "A. 16.9 miles B. 17.2 miles C. 10.6 miles D. 15.3 E. None of these. \n" );
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Algebra.Com's Answer #207451 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Some friends on a hike leave at 9am and return at 2pm. \n" ); document.write( " They spend one-quarter of the total distance walking uphill, one-half walking \n" ); document.write( " on level ground, and one-quarter walking downhill. if their speed is 4mph on \n" ); document.write( " level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk? \n" ); document.write( ": \n" ); document.write( "\"Some friends on a hike leave at 9am and return at 2pm.\"; therefore \n" ); document.write( "Total time of the walk = 5 hrs \n" ); document.write( ": \n" ); document.write( "let d = total distance \n" ); document.write( ": \n" ); document.write( "\"They spend one-quarter of the total distance walking uphill,\" \n" ); document.write( ".25d = walking uphill \n" ); document.write( ": \n" ); document.write( "\"one-half walking on level ground,\" \n" ); document.write( ".5d = walking level ground \n" ); document.write( ": \n" ); document.write( "\"and one-quarter walking downhill.\" \n" ); document.write( ".25d = walking up-hill \n" ); document.write( ": \n" ); document.write( "if their speed is 4mph on level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk? \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = dist/speed \n" ); document.write( " \n" ); document.write( "multiply by 12, results: \n" ); document.write( "3(.5d) + 6(.25d) + 2(.25d) = 12(5) \n" ); document.write( "; \n" ); document.write( "1.5d + 1.5d + .5d = 60 \n" ); document.write( ": \n" ); document.write( "3.5d = 60 \n" ); document.write( "d = \n" ); document.write( "d ~ 17.2 miles \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the total time: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2.15 + 2.15 + .717 = 5.02 ~ 5 hrs \n" ); document.write( " \n" ); document.write( " |