document.write( "Question 286016: Some friends on a hike leave at 9am and return at 2pm. They spend one-quarter of the total distance walking uphill, one-half walking on level ground, and one-quarter walking downhill. if their speed is 4mph on level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk?\r
\n" ); document.write( "\n" ); document.write( "A. 16.9 miles B. 17.2 miles C. 10.6 miles D. 15.3 E. None of these.
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Algebra.Com's Answer #207451 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Some friends on a hike leave at 9am and return at 2pm.
\n" ); document.write( " They spend one-quarter of the total distance walking uphill, one-half walking
\n" ); document.write( " on level ground, and one-quarter walking downhill. if their speed is 4mph on
\n" ); document.write( " level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk?
\n" ); document.write( ":
\n" ); document.write( "\"Some friends on a hike leave at 9am and return at 2pm.\"; therefore
\n" ); document.write( "Total time of the walk = 5 hrs
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\n" ); document.write( "let d = total distance
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\n" ); document.write( "\"They spend one-quarter of the total distance walking uphill,\"
\n" ); document.write( ".25d = walking uphill
\n" ); document.write( ":
\n" ); document.write( "\"one-half walking on level ground,\"
\n" ); document.write( ".5d = walking level ground
\n" ); document.write( ":
\n" ); document.write( "\"and one-quarter walking downhill.\"
\n" ); document.write( ".25d = walking up-hill
\n" ); document.write( ":
\n" ); document.write( "if their speed is 4mph on level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk?
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; Time = dist/speed
\n" ); document.write( "\".5d%2F4\" + \".25d%2F2\" + \".25d%2F6\" = 5
\n" ); document.write( "multiply by 12, results:
\n" ); document.write( "3(.5d) + 6(.25d) + 2(.25d) = 12(5)
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\n" ); document.write( "1.5d + 1.5d + .5d = 60
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\n" ); document.write( "3.5d = 60
\n" ); document.write( "d = \"60%2F3.5\"
\n" ); document.write( "d ~ 17.2 miles
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\n" ); document.write( "Check solution by finding the total time:
\n" ); document.write( "\".5%2817.2%29%2F4\" + \".25%2817.2%29%2F2\" + \".25%2817.2%29%2F6\" =
\n" ); document.write( "\"8.6%2F4\" + \"4.3%2F2\" + \"4.3%2F6\" =
\n" ); document.write( "2.15 + 2.15 + .717 = 5.02 ~ 5 hrs
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