document.write( "Question 34459: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #20744 by mukhopadhyay(490) ![]() You can put this solution on YOUR website! Nickels = x \n" ); document.write( "Dimes = y \n" ); document.write( ".05x+ .10y = 5.65 (based on total collection) \n" ); document.write( "=> 5x + 10y = 565.....(1) \n" ); document.write( "(.10)(2y)+(x+8)(.05) = 10.45 (Based on adjusted collection) \n" ); document.write( "=> .2y+.05x+.40 = 10.45 \n" ); document.write( "=> .2y+.05x = 10.05 \n" ); document.write( "=> 5x+20y = 1005.......(2) \n" ); document.write( "(2) minus (1) gives, \n" ); document.write( "10y = 440 \n" ); document.write( "=> y = 44; \n" ); document.write( "From (1) 5x = 565-10y = 565-440 = 125 \n" ); document.write( "=> x = 125/5 = 25; \n" ); document.write( "Answer: Number of dimes = 44; \n" ); document.write( " |