document.write( "Question 286063: There are two local companies that will walk your dog. Pets first charges a membership fee of $10 and $3 per walk. Doggy Day Care charges a $5 membership fee and $2 per walk. What number of walks will cost the same at each company? \n" ); document.write( "

Algebra.Com's Answer #207424 by Earlsdon(6294) $\"\"$ $\"About$

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Pets First's total charge (C) for x walks is:
\n" ); document.write( " $\"10%2B3x\"$
\n" ); document.write( "Doggy Day Care's toatal charge (C) for x walks is:
\n" ); document.write( " $\"5%2B2x\"$
\n" ); document.write( "If you set these two equal to each other, you will find your answer:
\n" ); document.write( " $\"10%2B3x+=+5%2B2x\"$ Solve for x: Subtract 2x from both sides.
\n" ); document.write( " $\"10%2Bx+=+5\"$ Subtract 10 from both sides.
\n" ); document.write( " $\"x+=+-5\"$
\n" ); document.write( "Now since you cannot have a negative number of walks, there is no solution to this problem. In other words, the costs can never be equal no matter how many dog walks are made! \n" ); document.write( "

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