document.write( "Question 286002: find three consecutive odd positive intergers such that 2 times the sum of all three is 153 less then the product of the first and second intergers \n" ); document.write( "
Algebra.Com's Answer #207401 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the smallest of the three integers. Then then next odd integer must be , and the one after that has to be \r
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\n" ); document.write( "\n" ); document.write( "The sum of the three is\r
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\n" ); document.write( "\n" ); document.write( "Two times the sum is then:\r
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\n" ); document.write( "\n" ); document.write( "The product of the first and second is:\r
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\n" ); document.write( "\n" ); document.write( "So, putting it all together:\r
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\n" ); document.write( "\n" ); document.write( "Standard form:\r
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\n" ); document.write( "\n" ); document.write( "Solve the factorable quadratic. Exclude the negative root because the problem asks for positive integers.\r
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