document.write( "Question 285772: Sparrows and pigeons sit on a fence. When 5 sparrows leave, there remain 2pigeons for every sparrow. Then 25 pigeons leave and the ratio of sparrows to pigeons becomes 3 : 1.What is the original number of birds?\r
\n" ); document.write( "\n" ); document.write( "A. 50 B. 48 C. 75 D. 30 E. None of these.
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Algebra.Com's Answer #207379 by ankor@dixie-net.com(22740)\"\" \"About 
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Sparrows and pigeons sit on a fence.
\n" ); document.write( " When 5 sparrows leave, there remain 2pigeons for every sparrow.
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\n" ); document.write( "What is the original number of birds?
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\n" ); document.write( "\"When 5 sparrows leave, there remain 2pigeons for every sparrow.
\n" ); document.write( "\"%28s-5%29%2Fp\" = \"1%2F2\"
\n" ); document.write( "Cross Multiply
\n" ); document.write( "p = 2(s-5)
\n" ); document.write( "p = 2s - 10
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\n" ); document.write( "\"Then 25 pigeons leave and the ratio of sparrows to pigeons becomes 3 : 1.
\n" ); document.write( "\"%28s-5%29%2F%28p-25%29\" = \"3%2F1\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "s-5 = 3(p-25)
\n" ); document.write( "s - 5 = 3p - 75
\n" ); document.write( "s = 3p - 75 + 5
\n" ); document.write( "s = 3p - 70
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\n" ); document.write( "Replace p with (2s-10) derived from the 1st ratio
\n" ); document.write( "s = 3(2s-10) - 70
\n" ); document.write( "s = 6s - 30 - 70
\n" ); document.write( "s = 6s - 100
\n" ); document.write( "100 = 6s - s
\n" ); document.write( "s = \"100%2F5\"
\n" ); document.write( "s = 20 sparrows
\n" ); document.write( "then
\n" ); document.write( "p = 2(20) - 10
\n" ); document.write( "p = 30 pigeons
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\n" ); document.write( "A total of 50 birds
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\n" ); document.write( "You can check the solutions in the two ratio statements
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