document.write( "Question 285772: Sparrows and pigeons sit on a fence. When 5 sparrows leave, there remain 2pigeons for every sparrow. Then 25 pigeons leave and the ratio of sparrows to pigeons becomes 3 : 1.What is the original number of birds?\r
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document.write( "A. 50 B. 48 C. 75 D. 30 E. None of these.
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Algebra.Com's Answer #207379 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Sparrows and pigeons sit on a fence. \n" ); document.write( " When 5 sparrows leave, there remain 2pigeons for every sparrow. \n" ); document.write( " \n" ); document.write( "What is the original number of birds? \n" ); document.write( ": \n" ); document.write( "\"When 5 sparrows leave, there remain 2pigeons for every sparrow. \n" ); document.write( " \n" ); document.write( "Cross Multiply \n" ); document.write( "p = 2(s-5) \n" ); document.write( "p = 2s - 10 \n" ); document.write( ": \n" ); document.write( "\"Then 25 pigeons leave and the ratio of sparrows to pigeons becomes 3 : 1. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "s-5 = 3(p-25) \n" ); document.write( "s - 5 = 3p - 75 \n" ); document.write( "s = 3p - 75 + 5 \n" ); document.write( "s = 3p - 70 \n" ); document.write( ": \n" ); document.write( "Replace p with (2s-10) derived from the 1st ratio \n" ); document.write( "s = 3(2s-10) - 70 \n" ); document.write( "s = 6s - 30 - 70 \n" ); document.write( "s = 6s - 100 \n" ); document.write( "100 = 6s - s \n" ); document.write( "s = \n" ); document.write( "s = 20 sparrows \n" ); document.write( "then \n" ); document.write( "p = 2(20) - 10 \n" ); document.write( "p = 30 pigeons \n" ); document.write( ": \n" ); document.write( "A total of 50 birds \n" ); document.write( ": \n" ); document.write( "You can check the solutions in the two ratio statements \n" ); document.write( " \n" ); document.write( " |