Algebra.Com's Answer #20737 by lyra(94)![\"\"](\"/images/stars/stars-08.gif\")  
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The definition of a perfect sqaure is \"A number whose square root is an integer\". We can test a few small integers, lets start with one, the smallest.  which is not a perfect square since  is not an integer. Thus it cannot be 1. Lets try 2,  ,  which is an integer. So 2 works for 2n, lets try it with 3n:  the cube root of 6 is not an integer, so it cannot be 2. Lets try 3, ,  is not an integer, so it cannot be 3. As we keep going down, we find a pattern, for 2n to work 2(some even number n)=perfect square. We can skip to 8=n, so  which is a perfect square, but 3 is not a perfect cube. This seems to be going pretty slowly, so lets try a different technique (don't be afraid in math to start over, and go down a different path, sometimes you just have to reorganize your thinking.) Lets try a different aproach:
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document.write( "lets go by cubes.
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document.write( " so n=9 might work,  oops, that wont work.  non-integer.  =non-integer.   okay two down, one to go,   darn, that won't work!  non-integer.  non-integer.   non-integer. non-integer. Now that you see the pattern you can keep on testing, \r
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document.write( "Good luck!\r
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document.write( "Hope this helps, this is a very difficult problem,
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document.write( "lyra \n" );
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