document.write( "Question 285937: Find the quadratic equation with roots which are the squares of the roots of
\n" ); document.write( "x^2 -5x -3 =0
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Algebra.Com's Answer #207344 by richwmiller(17219)\"\" \"About 
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x^2 -5x -3 =0
\n" ); document.write( "x^2 -5x =3
\n" ); document.write( "(5/2)^2=25/4
\n" ); document.write( "3=12/4
\n" ); document.write( "x^2-5x+25/4=3+25/4
\n" ); document.write( "(x-5/2)^2=37/4
\n" ); document.write( "x=5/2-sqrt(37/4)
\n" ); document.write( "x=5/2+sqrt(37/4)
\n" ); document.write( "c=1/2(5-sqrt(37))
\n" ); document.write( "d=1/2(5+sqrt(37))\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-5x%2B-3+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-5%29%5E2-4%2A1%2A-3=37\".
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\n" ); document.write( " Discriminant d=37 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--5%2B-sqrt%28+37+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+37+%29%29%2F2%5C1+=+5.54138126514911\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-5%29-sqrt%28+37+%29%29%2F2%5C1+=+-0.54138126514911\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-5x%2B-3\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-5x%2B-3+=+1%28x-5.54138126514911%29%2A%28x--0.54138126514911%29\"
\n" ); document.write( " Again, the answer is: 5.54138126514911, -0.54138126514911.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-5%2Ax%2B-3+%29\"

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\n" ); document.write( "\n" ); document.write( "let's call the roots c and d
\n" ); document.write( "so the new equation will have x^2 and y^2 as there roots
\n" ); document.write( "(a-c^2)*(b-d^2)=0
\n" ); document.write( "ab-bc^2-ad^2+c^2d^2=0
\n" ); document.write( "plug these in .
\n" ); document.write( "c=1/2(5-sqrt(37))
\n" ); document.write( "d=1/2(5+sqrt(37))\r
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